clocks , birds and spiders
there is a closed box with pigeons sitting inside. what happens to the weight of the box if the pigeons start flying?
if we begin at 12 noon and end at 12 midnight how many times would the two needles meet each other?
there is a cubical room. A spider is there at one corner who can only walk on the walls. He has to go to the farthest end (along diagonal).find the shortest path
if we begin at 12 noon and end at 12 midnight how many times would the two needles meet each other?
there is a cubical room. A spider is there at one corner who can only walk on the walls. He has to go to the farthest end (along diagonal).find the shortest path
posted by abhishek at 2:56 PM
18 Comments:
For the first question, I am afraid will have to specify the means by which you are measuring weight. If you are taking weight by measuring the mass and then multiplying it by the accelaration due to gravity at the point of measurement, then the stance of the birds is irrelevent. However, if you are measuring weight by using a conventional gravity-oriented measuring device, the weight will reduce.
Q2) Just count, I won't bother.
Q3) The length of the shortest path is the square root of five, times the side of the room, drawing an uninterrupted line from the first vertex, across two adjecent walls to the opposite vertex. The sqare root of five is 2.2360679774997896964091736687313, duly approximated.
q2 it' not just counting give the exact answer
q3 the answer isn't corrrect try again.i can't understand how u got the answer .please explain
q1 why would it be so?
I won't bother to explain q1, it has a lot to do with gravity.
Q3 is correct, unless your value is numerically smaller than mine, as this value most certainly exists.
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as far as i know the correct answer to q3 is side(1+square root of 2)
side(1+1.414)
side(2.414)
2:57 PM
2.23 is smaller than 2.414...
but what path gives 2.23
well argez i truly dont understand how there can possibly be two methods for measuring 'weight'.
according to what we read it in physics ...it is equivalent to the normal reaction of the earth to a body in contact .
here obviously the normal reaction will decrease on the flight of the birds .consequently the weight shall decreaese.
btw yor blog is very interesting .
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oh shit ..i thought that it did not get published...my computer was showing an error
but why would the the normal acceleration be different
you'll get the details of normal reaction in 11th...
what about the other two ques any more answers?
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